Posted by Anonymous on Saturday, January 24, 2009 at 9:07pm.
A(11,8)B(2,6) and C(19,8) are the vertices of Triangle ABC. N(X,Y) is a point on AC such the BN is Perpendicular to AC. Find Area of Triangle ABC. PLEASE HELP!!!

Math  bobpursley, Saturday, January 24, 2009 at 9:44pm
The second sentence is not needed.
Draw the triangle. Compute the side lengths
s1=AB= sqrt ((bxax)^2+(byay)^2 )
= sqrt ( 13^2 + (14)^2 )= sqrt (169+256)=20.6
and do that for all sides. Then knowing the sides, calculate the perimeter, divide by 2. Let that be p.
Area=sqrt (p(pa)(pb)(pc))
Or you can do it here
http://www.analyzemath.com/Geometry_calculators/perimeter_area_tri_verti.html