A(-11,8)B(2,-6) and C(-19,-8) are the vertices of Triangle ABC. N(X,Y) is a point on AC such the BN is Perpendicular to AC. Find Area of Triangle ABC. PLEASE HELP!!!
Math - bobpursley, Saturday, January 24, 2009 at 9:44pm
The second sentence is not needed.
Draw the triangle. Compute the side lengths
s1=AB= sqrt ((bx-ax)^2+(by-ay)^2 )
= sqrt ( 13^2 + (-14)^2 )= sqrt (169+256)=20.6
and do that for all sides. Then knowing the sides, calculate the perimeter, divide by 2. Let that be p.
Or you can do it here