Saturday
September 20, 2014

Homework Help: Math - natural log

Posted by Anonymous on Saturday, January 24, 2009 at 6:29pm.

Solve for x. (25e^0.1x)/(e^(0.1x) + 3) = 10

e^2.5x / (e^(0.1x) + 3) = 10
e^(2.5x - 0.1x) + 1/3 = 10
e^2.4x = 29/3
ln^(e^(2.4x)) = ln(29/3)
2.4x = ln(29/3)
x = 0.945

Is that correct?

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