Posted by **Anonymous** on Saturday, January 24, 2009 at 6:29pm.

Solve for x. (25e^0.1x)/(e^(0.1x) + 3) = 10

e^2.5x / (e^(0.1x) + 3) = 10

e^(2.5x - 0.1x) + 1/3 = 10

e^2.4x = 29/3

ln^(e^(2.4x)) = ln(29/3)

2.4x = ln(29/3)

x = 0.945

Is that correct?

- Math - natural log -
**Damon**, Saturday, January 24, 2009 at 6:35pm
Let e^.1 x = y

25 y /(y+3) = 10

25 y = 10 y + 30

15 y = 30

y = 2

so

e^.1 x = 2

ln e^.1x = ln 2

.1 x = ln 2

x = 10 ln 2

= 6.931

- Math - natural log -
**Ahmad**, Thursday, September 13, 2012 at 10:38pm
Express the given quantity as a single logarithm.

ln(1+x^8)+ln(x)- ln(sin(x))

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