Posted by Anonymous on Saturday, January 24, 2009 at 6:29pm.
Solve for x. (25e^0.1x)/(e^(0.1x) + 3) = 10
e^2.5x / (e^(0.1x) + 3) = 10
e^(2.5x - 0.1x) + 1/3 = 10
e^2.4x = 29/3
ln^(e^(2.4x)) = ln(29/3)
2.4x = ln(29/3)
x = 0.945
Is that correct?
Math - natural log - Damon, Saturday, January 24, 2009 at 6:35pm
Let e^.1 x = y
25 y /(y+3) = 10
25 y = 10 y + 30
15 y = 30
y = 2
e^.1 x = 2
ln e^.1x = ln 2
.1 x = ln 2
x = 10 ln 2
Math - natural log - Ahmad, Thursday, September 13, 2012 at 10:38pm
Express the given quantity as a single logarithm.
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