March 28, 2015

Homework Help: CHemistry....Please help

Posted by Saira on Saturday, January 24, 2009 at 1:15pm.


At 25C, the molar solubility of calcium phosphate in water is 1.1*10^{-7}M. Calculate the solubility in grams per liter.

I m not sure how to convert M to g/L


2.tert-Butyl alcohol is a solvent with a Kf of 9.10 C/m and a freezing point of 25.5 C. When 0.807g of an unknown colorless liquid was dissolved in 11.6 g of tert-butyl alcohol, the solution froze at 15.3 C.

Which of the following is most likely the identity of this unknown liquid?

a.ethylene glycol(molar mass=62.07g/mol)
b.1-octanol (molar mass = 130.22 g/mol)
c.glycerol (molar mass = 92.09 g/mol)
d.2-pentanone (molar mass = 86.13 g/mol)
e.1-butanol (molar mass = 74.12 g/mol)

so, molar mass= mass in grams/# of moles

I think im suppose to find the number of moles, using the given information :
Do i use Pi= MRT, and im not sure what Kf stands for.

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