Friday
October 31, 2014

Homework Help: CHemistry....Please double check DrBobb

Posted by Saira on Saturday, January 24, 2009 at 1:06pm.

What mass of ethylene glycol C2H6O2, the main component of antifreeze, must be added to 10.0 L water to produce a solution for use in a car's radiator that freezes at -23C? Assume density for water is exactly 1g/mL.


First we find out the freezing point:
=(-23.0)-(0.0_
=-23.0 degrees C

Calculate target Colligative Molarity:
= -23=1.86 * Cm
= 12.37= Cm.

i* molality
i= 1

12.37= 1*m
12.37= m

molality= moles of solute(C2H6O2)/kg of solvent water

12.37m= moles C2H6O2/ 10.0kg water
123.7= moles of C2H6O2

123.7moles C2H6O2 * 62.26g C2H6O2
= 7701.56 g of C2H6O2

I think this number is quite high can someone please double check to see if i got the answer right.

Thank YOu

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