Posted by **Mary** on Friday, January 23, 2009 at 11:56am.

Th weekly salaries of a sample of 100 recent graduates of a private women's college are normally distributed with a mean of $600 and a standard deviation of $80. Determine the interval about the sample mean that has a 1% level of confidence. Use t=2.58

Not sure if this is correct?

=600+or-2.58(80)/10

=600+or-206.4/10

=600+or-20.64

- Pre-calculus -
**drwls**, Friday, January 23, 2009 at 1:37pm
I am not sure what "t" is supposed to be, but the interval that the salary will be in 99% of the time is 600 + or - 206.4

206.4 happens to be 2.58 times the standard deviation.

Your t may be what other texts usually call s, the deviation from the mean divided by sigma

## Answer This Question

## Related Questions

- Math - The weekly salaries of 100 recent graduates of a private women's college ...
- Math - The weekly salaries of 100 recent graduates of a private women's college ...
- STAT - 1. In a study of the income of U.S. factory workers, a random sample of ...
- statistics - The National Center for Education surveyed 4400 college graduates ...
- statistik - the average starting salary of this yaer's graduates of a large ...
- math - The National Center for Education surveyed 4400 college graduates about ...
- stastics - Salaries of 31 college graduates who took a course in college have a ...
- Statistics Question (Confidence Interval) - A sample of 15 recent college ...
- statistics - Determine the 90% confidence interval for a sample, taken from a ...
- statistics - Determine the 90% confidence interval for a sample, taken from a ...

More Related Questions