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January 25, 2015

January 25, 2015

Posted by **gagan** on Thursday, January 22, 2009 at 9:30pm.

can you plz help

thx I really am thankful to have found a forum that really cares. Thanks

- Math -
**Reiny**, Thursday, January 22, 2009 at 10:09pmLet the speed of the plane with no wind be x km/h

let the speed of the wind be y km/h

then into the wind, the actual speed of the plane is x-y km/h

and 960/(x-y) = 10/3 which reduces to

x - y = 286 (31)

with the wind:

960/(x+y) = 5/2 which reduces to

x + y = 384 (#2)

add #1 and #2 to get 2x = 672

x = 336, subbing back I got y = 48

so the speed of the plane is 336 km/h

and the speed of the wind is 48 km/h

check: (10/3)(336-48) = 960

(5/2)(336+48) = 960

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