Posted by gagan on Thursday, January 22, 2009 at 9:30pm.
Let the speed of the plane with no wind be x km/h
let the speed of the wind be y km/h
then into the wind, the actual speed of the plane is x-y km/h
and 960/(x-y) = 10/3 which reduces to
x - y = 286 (31)
with the wind:
960/(x+y) = 5/2 which reduces to
x + y = 384 (#2)
add #1 and #2 to get 2x = 672
x = 336, subbing back I got y = 48
so the speed of the plane is 336 km/h
and the speed of the wind is 48 km/h
check: (10/3)(336-48) = 960
(5/2)(336+48) = 960
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