how do you do this question

An aqueous solution of calcium chloride contains 2 grams of calcium chloride ( molar mass 110.98 g mol-1)
in 100 ml calculate the concentration of chloride ion (Cl-) in the solution

2 g CaCl2 is how many moles?

2 g/molar mass CaCl2 = ?? moles.
M = moles/L = ??moles/0.100 L (that's the 100 mL).
M Cl^- is twice that of the CaCl2 since there are two moles Cl^- per mole CaCl2.
Post your work if you need further assistance.

To calculate the concentration of chloride ions (Cl-) in the solution, you need to first determine the number of moles of calcium chloride present in the solution, and then use stoichiometry to find the number of moles of chloride ions.

Here's how you can calculate the concentration of chloride ions:

Step 1: Calculate the number of moles of calcium chloride:
Given: Mass of calcium chloride = 2 grams
Molar mass of calcium chloride = 110.98 g/mol

Number of moles of calcium chloride = Mass of calcium chloride / Molar mass of calcium chloride
Number of moles of calcium chloride = 2 g / 110.98 g/mol

Step 2: Convert the volume of the solution to liters:
Given: Volume of solution = 100 ml

Volume of solution in liters = 100 ml / 1000 ml/L
Volume of solution in liters = 0.1 L

Step 3: Calculate the concentration of chloride ions:
Given: Calcium chloride (CaCl2) dissociates into 2 moles of chloride ions (Cl-) per mole of calcium chloride.

Concentration of chloride ions (Cl-) = (Number of moles of calcium chloride * 2) / Volume of solution
Concentration of chloride ions (Cl-) = (2 g / 110.98 g/mol) * 2 / 0.1 L

Now, you can calculate the concentration of chloride ions by plugging in the values into this equation.