Posted by **Julie** on Wednesday, January 21, 2009 at 8:40pm.

Suppose a random variable X has a cumulative distribution function given by

F(a) = {0 for a<0, 1/2 for 0<=a<1, 3/5 for 1<=a<2, 4/5 for 2<=a<3,

9/10 for 3<=a<3.5, 1 for 3.5<=a.

a. Find the probability mass function for X.

b. Find the probability that a given observation of the value of X is greater than or equal to 1.5.

- Probability -
**economyst**, Thursday, January 22, 2009 at 10:47am
I'm confused. I think to answer this question, we need to know the range of your variable a. Does a go from -infinity to +3.5?

- Probability -
**economyst**, Thursday, January 22, 2009 at 2:44pm
Nevermind, I get it.

P(x) = 5/10 for 0<= x < 1

= 1/10 for 1<= x < 2

= 2/10 for 2<= x < 3

= 1/10 for 3<= x < 3.5

= 1/10 for 3.5<= x

P(x>1.5) = 5/10

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