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December 20, 2014

December 20, 2014

Posted by **Lola** on Wednesday, January 21, 2009 at 1:55pm.

I need to find fog, gof, gog, and fof and their domains for the following:

f(x) = square root of 2x +3

g(x) = x^2 + 1

if someone can help me asap that would be so great!

- Calculus -
**drwls**, Wednesday, January 21, 2009 at 4:42pmFor g of f, substitute sqrt(2x +3) for x in g(x)

You get (2x + 3) + 1 = 2x + 4

The domain is all numbers in thnis case.

Do the others the same way. We will gladly critique your work.

- Calculus -
**Lola**, Wednesday, January 21, 2009 at 4:58pmokay, so i tried out subtsting x into f (x) and i got sqrt (2x^2 +5)..is that right?

and what do u mean domain is all in numbers?

can u help me with the f o f and g og?

and a side question, we got a table of values that was something like

x 1 2 3 4 5 6

f(x) 3 1 .....

g(x) 6

so the first question is like evaulaute:

f(g(1))

would that be

3(6)?

- Calculus -
**drwls**, Wednesday, January 21, 2009 at 5:11pmAre you trying to calculate f of g(x)?

Assuming f(x) = sqrt(2x+3) and not sqrt (2x) + 3, f of g(x) would be

sqrt [2(x^2 +1) + 3]= sqrt (2x^2 + 5)

So you would be correct.

g of g(x) = (x^2+1)^2 +1 = x^2 + 2x + 2

To your side question: yes, the first answer is 18.

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