An aqueous solution of calcium chloride contains 2 g of calcium chloride (molar mass 110.98 g mol-1) in 100 ml. Calculate the concentration of chloride ion in the solution

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How many mols in 2 g CaCl2?

2 g x (110.98 g CaCl2/1 mol CaCl2) = ?? mols
M = # mols/L = ??mols/0.100 L = xx molar.

There are two mols Cl^- per 1 mol CaCl2; therefore, (Cl^-) is twice that for CaCl2.

To calculate the concentration of chloride ion in the solution, we need to first calculate the number of moles of calcium chloride present in the solution.

Given:
Mass of calcium chloride (CaCl2) = 2 g
Molar mass of CaCl2 = 110.98 g mol-1

Using the formula:

Number of moles = Mass / Molar mass

Number of moles of CaCl2 = 2 g / 110.98 g mol-1
= 0.018 mol

Since calcium chloride dissociates in water to form two chloride ions (Cl-), the concentration of chloride ions will be twice the concentration of calcium chloride.

Now, we need to calculate the volume of the solution in liters to determine the concentration of chloride ions.

Given:
Volume of the solution = 100 ml = 100/1000 = 0.1 L

Concentration of chloride ions (Cl-) = 2 * (Number of moles of CaCl2) / Volume of solution

Concentration of chloride ions = 2 * (0.018 mol) / 0.1 L
= 0.36 mol/L

Therefore, the concentration of chloride ions in the solution is 0.36 mol/L.