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December 18, 2014

December 18, 2014

Posted by **syd** on Tuesday, January 20, 2009 at 10:41pm.

- precalc -
**Reiny**, Tuesday, January 20, 2009 at 11:04pmI will do one of the combinations for you

front: 40 teeth

back wheel: 12 teeth

(this will be the gear that can produce the highest speed)

for each turn of the front sprocket the back wheel will turn 40/12 or 10/3 or 3 1/3 times

each revolution of the back wheel covers

2(26)pi inches or 163.3628 inches

so at 130 rpm of the front sprocket, the back will will cover

130(10/3)163.3628 inches/minute

= 1.117275 miles/min (I divided by 5280*12)

~= 67 mph (I multiplied by 60)

you do the rest,

can you see the only part that would change ???

- precalc -
**drwls**, Wednesday, January 21, 2009 at 10:41amI think Reiny used the rire diameter for the radius, so the speed is two tiomes too high.

This question was posted and answered previously

- precalc -
**drwls**, Wednesday, January 21, 2009 at 10:44amSee your other post at http://www.jiskha.com/display.cgi?id=1232509956

- zubdce jlek -
**zubdce jlek**, Tuesday, February 10, 2009 at 5:50pmmfyelko sgpcyq earwxfs gaexz eqklximt okfudm zndb

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