A wheel of diameter 0.700 meters rolls without slipping. A point on the top of the wheel moves with a tangential speed of 2.00 m/s with respect to the ground.

1. If the wheel suddenly stops spinning and skis along the ground then
a. v=rù
b. v>rù
c. v<rù

thank you

THE wheel is not spinning, so the point on the top of the wheel is moving at the same speed as the wagon, and angular velocity of course is zero. This is an odd question.

so is it A B OR C

ANGULAR Velocity is zero. Repeat, angular velocity is zero. IS V zero?

and,make certain the question is typed wrong. This is indeed a very odd question.

What do v and ù represent? The dimensions don't even make sense. Putting a dot above a number usually represents a rate of change.

I think the idea is that the final speed of the top of the wheel is less than it was when it was rolling.

To answer this question, we need to understand the relationship between the linear speed, tangential speed, and angular speed of a rotating object.

Linear speed (v) refers to the speed at which a point on the object moves in a straight line, usually with respect to the ground. Tangential speed (vₜ) refers to the speed at which a point on the object moves tangent to the circular path of the object. Angular speed (ω) is the rate at which the object rotates, usually measured in radians per second (rad/s).

The relationship between these three quantities is given by the formula v = rω, where v is the linear speed, r is the radius of the circular path, and ω is the angular speed.

In this problem, we are told that a point on the top of the wheel has a tangential speed of 2.00 m/s with respect to the ground. We are also given the diameter of the wheel, which is 0.700 meters.

To find the angular speed (ω) of the wheel, we need to calculate the radius (r) using the formula r = d/2, where d is the diameter.

Let's calculate the radius:
r = d/2 = 0.700/2 = 0.350 meters

Now, we can use the given tangential speed and the calculated radius to find the angular speed:
vₜ = rω => 2.00 = 0.350ω => ω = 2.00/0.350 ≈ 5.71 rad/s

Now let's address the main question. If the wheel suddenly stops spinning and skids along the ground, it means that the angular speed (ω) becomes zero. Since the angular speed is zero, the linear speed (v) becomes zero as well because v = rω.

Therefore, the correct answer is c. v < rω