Posted by strawerryfields on Tuesday, January 20, 2009 at 5:52pm.
sub the second equation into the first, so
x = 3 - (x-3)^2
x = 3 - (x^2 - 6x + 9)
x^2 - 5x + 6 = 0
(x-2)(x-3) = 0
x = 2 or x = 3
if x = 2, then y = 2-3 = -1
if x = 3, then y = 3-3 = 0
so they intersect at (2,-1) and (3,0)
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