Posted by **Liz** on Tuesday, January 20, 2009 at 11:12am.

Find the first three iterates of the function f(x)=x^2-2, if the intial value is -2.

z(0)=-2

z(1)=(-2)^2-2 or 4-2=2

z(2)=(2)^2-2 or 4-2=2

z(3)=(2)^2-2 or 4-2=2

Answer: z(1)=2, z(2)=2, z(3)=2

- Pre-calculus -
**bobpursley**, Tuesday, January 20, 2009 at 11:36am
correct.

- Pre-calculus -
**Liz**, Tuesday, January 20, 2009 at 11:49am
Thanks

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