Monday

October 20, 2014

October 20, 2014

Posted by **Mary** on Tuesday, January 20, 2009 at 10:35am.

3[cos5pi/12+isin5pi/12] divided by 6[cospi/12+isinpi/12]. Express the quotient in rectangular form.

I worked it out as:

1/2[cospi/3+isinpi/3]

=1/2(1/2+1/2i)

=1/2+1/2i

Is this right?

- Pre-calculus -
**drwls**, Tuesday, January 20, 2009 at 11:42amYou started out OK but went astray somewhere.

Here's one way to do it.

Rewrite it as

(1/2)e^(i*5 pi/12)/e^(i*pi/12)

= (1/2)e^(i*pi/3)

= (1/2)[cos (pi/3)+ i sin(pi/3)]

You got that far..

= (1/2)[(1/2) + i(sqrt3)/2]

1/4 + i (1/4)* sqrt3

- Pre-calculus -
**Liz**, Tuesday, January 20, 2009 at 11:48amOk thanks i know where i went wrong

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