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April 1, 2015

April 1, 2015

Posted by **vero** on Monday, January 19, 2009 at 9:29pm.

please check my answer

a) explain these events are either dependent or independent.

i think this is independent because the coach just randomly chooses the ball.

b) what is the propability both of the balls will be the ame design color?

is it 98/15.....

- algebra...urgent help -
**Reiny**, Monday, January 19, 2009 at 9:34pm - algebra...urgent help -
**Damon**, Monday, January 19, 2009 at 9:42pmThe result of the second reach into the bag depends on the result of the first reach.

For example if the coach pulled a black one first, then for the second there would be 7 black and 7 red.

probability first one black = 8/15

then probability second one black = 7/14

so 8/15 * 7/14 for both black

probability first one not black = 7/15

probability second one not black = 6/14

so 7/15 * 6/14 for both white

add those two.

8/15 * 7/14 + 7/15 * 6/14

= (1/15)(56/14 + 42/14) = (1/15)(98/14)

= 98/210 = 49/105

- algebra...urgent help -
**Damon**, Monday, January 19, 2009 at 9:43pmOh, 49/105 = 7/15

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