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Posted by on Monday, January 19, 2009 at 6:58pm.

Hey I need help factoring 5x^4-180x^2. I'm used to factoring with three numbers, and not two. How would you do just two like this? Thanks

  • Math-Factoring - , Monday, January 19, 2009 at 7:14pm

    first of all I see a common factor of 5x^2
    so
    5x^4-180x^2
    = 5x^2(x^2 - 36)

    Now isn't that a difference of squares???

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