Post a New Question


posted by .

In a Cavendish balance apparatus suppose that M1= 1.10Kg, M2= 25.0Kg, and the rod connecting the M1 pairs is 30.0cm long. If, in each pair, M1 and M2 are 12.0cm apart center-to-center, find (a) the net force and (b) the net torque (about the rotation axis) on the rotating part of the apparatus. (c) Does is seem that the torque in part (b) would be enough to easily rotate the rod? Suggest some ways to improve the sensitivity of this experiment.

  • Physics -

    You can use Newtons equation to find the force of attraction.
    Then, torque=2*force*15cm

Answer This Question

First Name:
School Subject:

Related Questions

More Related Questions

Post a New Question