Monday

January 26, 2015

January 26, 2015

Posted by **Mary** on Monday, January 19, 2009 at 7:22am.

my answer is:

coordinates of center: (-3,1)

foci:(-11,-1) and (4.7,-1)

vertices: (-11,-1) (5,-1)

(-3,-1+-square root of 5)

not sure how to graph, i know the center is (-3,1)

- Pre-calculus -
**drwls**, Monday, January 19, 2009 at 8:43am5(x^2 + 6x + 9) + 64(y^2 + 2x + 1) -45 -64 -211 = 0

5(x+3)^2 + 64 (y+1)^2 = 320

(x+3)^2/64 + (y+1)^2/5 = 0

Shouldn't the center be at (-3, -1) ?

The semimajor axis length (along the x direction) is a = sqrt64 = 8 and the semiminor axis length is b = sqrt5. The foci are at y = -1, and x = -3 +/- c, where

c^2 = a^2 - b^2 = 64 - 5 = 59

Add and subtract the semimajor axis lengths from the center coordinate to get the vertex locations.

I can't help you with the graphing part. You will need to locate the center on a graph, plot the vertex locations, and compute the coordinates of some intermediate points along the curve.

It is possible that I have made some math errors myself, so check my work.

**Answer this Question**

**Related Questions**

Pre-calculus-ck answers - Identify the graph of the equation 4x^2-25y^2=100. ...

Pre-Calculus - Find the coordinates of the center, the foci, the vertices, and ...

Pre-Calculus - I am having trouble with several problems: 1) Find the ...

Pre-Calculus - I am having trouble with several problems: 1) Find the ...

Pre-calc - Heres the equation: (x^2)-(4y^2)-(4x)+(24y)-(36)=0 Your supposed to ...

Math - Find the center, vertices, foci, and eccentricity of the ellipse. 9x^2 + ...

Math - 9x^2+16y^2-18x+64y-71=0 find the coordinates of the center, the foci, and...

Algebra II-Please check - I'm sorry the computer jammed on an earlier post and I...

Pre-Cal - Find the standard form of the equation of the ellipse. (Remember ...

Algebra 2 - Choose the equation that best represents an ellipse for the given ...