Posted by Anonymous on Monday, January 19, 2009 at 4:17am.
how do i solve for t:
.50=1e^(t/125)^5
i got this far:
ln(.5)=5ln(t/125)
t=?

math ln  Damon, Monday, January 19, 2009 at 5:59am
5 e^(t/5^2) = 1.5
e^(t/125) = .3
e^(t/125) = 1/.3 = 3.3333
t/125 = ln 3.3333
t = 150.5