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March 29, 2015

March 29, 2015

Posted by **Anonymous** on Monday, January 19, 2009 at 4:17am.

-.50=1-e^-(t/125)^5

i got this far:

ln(.5)=5ln(-t/125)

t=?

- math ln -
**Damon**, Monday, January 19, 2009 at 5:59am5 e^-(t/5^2) = 1.5

e^-(t/125) = .3

e^(t/125) = 1/.3 = 3.3333

t/125 = ln 3.3333

t = 150.5

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