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posted by Anonymous on Monday, January 19, 2009 at 4:17am.
how do i solve for t: -.50=1-e^-(t/125)^5 i got this far: ln(.5)=5ln(-t/125) t=?
5 e^-(t/5^2) = 1.5 e^-(t/125) = .3 e^(t/125) = 1/.3 = 3.3333 t/125 = ln 3.3333 t = 150.5
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