precalculus
posted by Mary .
Graph the polar equation: 2=r cos(theta + 180)
2=r(costheta cos180+sintheta sin180)
2=r(1/2costheta +pi+ pi sintheta)
2=1/2rcostheta + pi rsintheta
2=1/2x+ pi y
4=x+ pi
0= x + pi4
how do i graph?

trig identity is
cos (a+b) = cos a cos b  sin a sin b
I think you have the sign wrong.
use pi radians for 180 deg
let t = theta
2 = r (cos t cos pi  sin t sin pi)
cos pi = 1 and sin pi = 0
2 = r ( cos t)
r cos t = 2
x = 2
vertical line through x = 2
note y = r sin t
so y = (2/cos t)sin t
y = 2 tan t
tan t takes all values from oo to +oo as t goes from 0 to 2 pi. In other words the entire vertical line. 
Thank you I understand now.

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