Posted by Jack on .
Draw a lewis structure for BrO4- in which all atoms have the lowest formal changes. Indicate the values of nonzero formal charges and include lonepair electrons.
It is almost impossible to draw lewis structures on these boards due to the spacing problem. Here is a structure for BrO3^- from Purdue.
To the ball and stick model drawn there, if you will change each line to a pair of electrons, and add a pair of electrons to the top, left, and bottom of the left and right oxygen atom, add a pair of electrons to the lowest oxygen at the left, right, and bottom, then add the final two electons to the top of the Br atom, you will have the structure. Finally, add a negative charge to the ion. You should have 25 electrons total. I hope this helps.