3-6(t-7)= 8-5(2t+1)
7x+26-5x = 5x-2+x
I am not sure how to start these.
Any help?
Get rid of parentheses and combine like terms.
3 - 6(t-7) = 8 - 5(2t+1)
3 - 6t + 42 = 8 - 10t -5
42 = -4t
You should be able to continue from here and do the same process with the second equation.
I hope this helps. Thanks for asking.
multiply out parentheses first
3 - 6 t + 42 = 8 - 10 t - 5
combine like terms on left and on right
45 - 6 t = 3 - 10 t
add 10 t to both sides
45 + 4 t = 3
subtract 45 from both sides
4 t = - 42
divide both sides by 4
t = - 10.5
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check
3 - 6 (-10.5-7) = 8 - 5 (2*-10.5 + 1) ????
3 + 63 + 42 = 8 +105 - 5 ???
108 = 108 check Caramba !
To solve these equations, you can follow the steps below:
1. Simplify both sides of the equation by distributing the numbers outside the parentheses to the terms inside.
For the first equation:
3 - 6(t - 7) = 8 - 5(2t + 1)
3 - 6t + 42 = 8 - 10t - 5
-6t + 45 = -2 - 10t
For the second equation:
7x + 26 - 5x = 5x - 2 + x
7x - 5x + 26 = 6x - 2
2. Combine like terms on each side of the equation.
For the first equation:
-6t + 45 = -2 - 10t
Add 10t to both sides:
4t + 45 = -2
Subtract 45 from both sides:
4t = -2 - 45
4t = -47
For the second equation:
7x - 5x + 26 = 6x - 2
Combine like terms on each side:
2x + 26 = 6x - 2
Subtract 2x from both sides:
26 = 4x - 2x
26 = 2x
3. Solve for the variable by isolating it on one side of the equation.
For the first equation:
4t = -47
Divide both sides by 4:
t = -47/4
For the second equation:
26 = 2x
Divide both sides by 2:
x = 26/2
x = 13
Therefore, for the first equation, the solution is t = -47/4, and for the second equation, the solution is x = 13.