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electric field intensity

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Two 2.0 g spheres are suspended by 10.0 cm long light strings. A uniform electric field is applied in the x direction. If the spheres have charges of -5.0 10-8 C and +5.0 10-8 C, determine the electric field intensity that enables the spheres to be in equilibrium at = 10°.

  • electric field intensity - ,

    Mass of sphere = 2*10^-3 kg
    Weight of sohere = 9.8*2 *10^-3 = 1.96 *10^-2 N
    Force to hold at 10deg = 1.96*10^-2 * tan 10
    = 3.45 *10^-3 N
    = E * q
    so
    E = 3.45 *10^-3 / 5 *10^-8

  • electric field intensity - ,

    6.91*10^4 N/C

  • electric field intensity - ,

    Follow the same process

    F:Static electricity force which the sphere receives
    F=qE+kq^2/r^2
    (r=8*10^(-2)×sin11°×2)
    sin11°=0.190

    the weight of the sphere: mg
    (=3*10^(-3)×9.8N)

    F/mg=tan11°(=0.194)
    F=tan11°*mg
    qE-kq^2/r^2= tan11°*mg
    E=kq/r^2+tan11°*mg/q

    =2.90*10^5+1.90*10^5
    =4.80*10^5(N/m)

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