Wednesday
April 16, 2014

Homework Help: Biochemistry

Posted by Andrew on Saturday, January 17, 2009 at 10:09am.

Calculate the pH that would result if 0.40mL of 1.50 M HCl is added to 12.0 mL of a 0.065 M solution of the fully deprotonated form of the tripeptide glu-asn-leu.

I know I'm supposed to do an ICE table... and the equation will look like this initially:

deprotonated + HCl ---> protonated + Cl
0.00078 mols 0.06 mols 0 0

but I'm not sure where to go from there! I also know I'm supposed to use the formula pH= pKa + log (deprotonated)/(protonated).

Thanks for any help

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