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Posted by on Friday, January 16, 2009 at 7:21pm.

The formation of CsCl from Cs(s) and Cl2(g) involves the following steps:
1. Cs(s)-Cs(g)
2. 1/2 Cl2(g)-Cl(g)
3. Cs(g) –Cs^+(g) + e^-
4. Cl(g) + e^- - Cl^-(g)
5. Cs^+(g) +Cl^-(g)-CsCl(s)
Which of these steps absorb energy and which release energy?

  • Chem help - , Friday, January 16, 2009 at 7:22pm

    See my response to your earlier duplicate post. You can't cut and paste.

  • Chem help - , Friday, January 16, 2009 at 7:22pm

    The formation of CsCl from Cs(s) and Cl2(g) involves the following steps:


    1.Cs(s)-Cs(g)
    2.1/2 Cl2(g)-Cl(g)
    3.Cs(g) –Cs^+(g) + e^-
    4.Cl(g) + e^- - Cl^-(g)
    5.Cs^+(g) +Cl^-(g)-CsCl(s)

    Which of these steps absorb energy and which release energy?

  • Chem help - , Friday, January 16, 2009 at 7:55pm

    See my response to iuyter just a few posts above.

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