Post a New Question

posted by mike on Friday, January 16, 2009 at 1:09am.

A 3.00x10^-3kg lead bullet travels at a speed of 2.40x10^2m/s and hits a wooden post. if half the heat energy generated remains with the bullet, what is the increase in temperature of the embedded bullet?(ci=1.28x10^2 j/kg degrees C

Compute the kinetic energy of the bullet. Take half of that value as heat added to the bullet, Q. Q = (1/2) M V^2 From that Q and the specific heat C and mass, compute the temperature rise, delta T. delta T = Q /(M C) = (1/2) V^2/C

225

112.5, BIATCHES

More Related Questions