Posted by **Enrique** on Thursday, January 15, 2009 at 9:53pm.

At a particular temperature, K = 3.75 for the following reaction.

SO2(g) + NO2(g)= SO3(g) + NO(g)

If all four gases had initial concentrations of 0.840 M, calculate the equilibrium concentrations of the gases.

- chemistry -
**bobpursley**, Thursday, January 15, 2009 at 10:01pm
K= (.84+x)^2 /(.84-x)^2

take the square root of each side, then

sqrtK=(.84+x)/(.84-x)

and you can multipy both sides by .84-x and then solve for x.

Knowing x, you can then find the concentration of each product (either add or subtract x from .84)

check my thinking.

- chemistry -
**GK**, Thursday, January 15, 2009 at 10:05pm
K = [SO3][NO / [SO2][NO2]] = 3.75

Let the moles of each reactant = x

[0.840+x][0.840+x] / [0.840-x][0.840-x] = 3.75

a) Solve for x.

b) To get the concentration of each reactant, subtract the value of x from 0.840M.

c) To get the concentration of each product, add the value of x to 0.840M.

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