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At a particular temperature, K = 3.75 for the following reaction.
SO2(g) + NO2(g)= SO3(g) + NO(g)

If all four gases had initial concentrations of 0.840 M, calculate the equilibrium concentrations of the gases.

  • chemistry - ,

    K= (.84+x)^2 /(.84-x)^2

    take the square root of each side, then

    and you can multipy both sides by .84-x and then solve for x.
    Knowing x, you can then find the concentration of each product (either add or subtract x from .84)
    check my thinking.

  • chemistry - ,

    K = [SO3][NO / [SO2][NO2]] = 3.75
    Let the moles of each reactant = x
    [0.840+x][0.840+x] / [0.840-x][0.840-x] = 3.75
    a) Solve for x.
    b) To get the concentration of each reactant, subtract the value of x from 0.840M.
    c) To get the concentration of each product, add the value of x to 0.840M.

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