Thursday
December 18, 2014

Homework Help: Chem/math question - from Sam

Posted by Writeacher on Thursday, January 15, 2009 at 8:43pm.

For the following reaction at 600. K, the equilibrium constant, Kp, is 11.5.
PCl5(g) = PCl3(g) + Cl2(g)

Suppose that 2.510 g of PCl5 is placed in an evacuated 470. mL bulb, which is then heated to 600. K.
(a) What would be the pressure of PCl5 if it did not dissociate?
___atm
(b) What is the partial pressure of PCl5 at equilibrium?
___ atm
(c) What is the total pressure in the bulb at equilibrium?
___atm
(d) What is the degree of dissociation of PCl5 at equilibrium?
___%



i got a to be 1.263 but i cnat find b or c and i didnt get to d yet
im having a lot of trouble! help!!

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