April 20, 2014

Homework Help: Chem/math question - from Sam

Posted by Writeacher on Thursday, January 15, 2009 at 8:43pm.

For the following reaction at 600. K, the equilibrium constant, Kp, is 11.5.
PCl5(g) = PCl3(g) + Cl2(g)

Suppose that 2.510 g of PCl5 is placed in an evacuated 470. mL bulb, which is then heated to 600. K.
(a) What would be the pressure of PCl5 if it did not dissociate?
(b) What is the partial pressure of PCl5 at equilibrium?
___ atm
(c) What is the total pressure in the bulb at equilibrium?
(d) What is the degree of dissociation of PCl5 at equilibrium?

i got a to be 1.263 but i cnat find b or c and i didnt get to d yet
im having a lot of trouble! help!!

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