Posted by **y912f** on Thursday, January 15, 2009 at 5:00pm.

im really stuck on these, can anyone help me and also explain how to solve them:

Find the exact values of s in the given intervals that have the given circular function values.

1. [pi/2, pi]; sin s=sqrt2/2

2. [pi/2, pi]; cos s=-sqrt3/2

thnks:)

- trigonometry -
**Damon**, Thursday, January 15, 2009 at 7:44pm
sqrt 2 is the legs of a 45,45, 90 triangle, hypotenuse is 2

sqrt 3 is the side opposite the 60 degree angle in a 30,60, 90 triangle. (legs are 1 and sqrt 3, hypotenuse is 2)

Learn those right triangles by heart. They come up constantly.

- trigonometry -
**y912f**, Thursday, January 15, 2009 at 7:52pm
how does that help me find s though..

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