Write the point-slope form of an equation for a line that passes through each point with the given slope. (2,2),m=-3
This is one example, I'm not sure how to do this.
http://www.jiskha.com/display.cgi?id=1231984921
slope = (y-2)/(x-2)
and
slope = -3
so
(y-2) / (x-2) = -3
You can expand that out to get the y = m x + b form
y - 2 = - 3 x + 6
y = -3 x + 8
To write the point-slope form of an equation for a line that passes through a given point (x₁, y₁) with a given slope m, you can use the formula:
y - y₁ = m(x - x₁)
In this case, the given point is (2, 2) and the slope is -3. Plugging these values into the formula, we get:
y - 2 = -3(x - 2)
This is the point-slope form of the equation for a line that passes through the point (2, 2) with a slope of -3.
To find the point-slope form of an equation for a line that passes through a given point (x₁, y₁) with a given slope m, you can use the formula:
y - y₁ = m(x - x₁)
Let's use this formula to find the equation for the line that passes through the point (2, 2) with a slope of -3.
Step 1: Plug in the given values into the formula.
y - 2 = -3(x - 2)
Step 2: Simplify the equation.
y - 2 = -3x + 6
Step 3: Rearrange the equation to the standard form.
3x + y = 8
So, the point-slope form of the equation for the line passing through (2,2) with a slope of -3 is y - 2 = -3(x - 2), which can also be written as 3x + y = 8.