What is the derivative of square root x ?
f(x)= x^n
f'= n x^(n-1)
Doesn't n= 1/2 in the squareroot case?
Oh now I see Thank You
Oh pardon me i meant to ask what is the anti-derivative of square root x
To find the derivative of the square root of x, we can use the power rule. The power rule states that if we have a function of the form f(x) = x^n, where n is a constant, then the derivative of f(x) with respect to x is given by f'(x) = n*x^(n-1).
In this case, we have f(x) = sqrt(x), or equivalently, f(x) = x^(1/2). Now, we can apply the power rule and find the derivative:
f'(x) = (1/2)*x^((1/2)-1)
= (1/2)*x^(-1/2)
= (1/2)*(1/sqrt(x))
= 1/(2*sqrt(x))
Therefore, the derivative of the square root of x is 1/(2*sqrt(x)).