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algebra II

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Find the equation of the line


With a slope of (-1/3) that goes through the point (2, -4)

With a slope of 3 that goes through the point (-5, -1)

  • algebra II - ,

    y=mx+b

    (x,y)

    You multiply x by m, the slope.
    You get to y by adding b.

    (2,-4)

    You multiply 2 (x) by -1/3 (m), the slope.
    You get to -4 (y) by adding -3.33 (b) = -10/3

    Therefore, y=(-1/3)x-(10/3)

    The next one is done the same way.

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