Posted by **Jane** on Sunday, January 11, 2009 at 8:09pm.

Consider curve given by

x^2+ 4y^2= 7 + 3xy..

Three part question

A) show that dy/dx = 3y-2x/8y-3x

B) Show that there is a point P with

x-coordinate 3 at whiich the line tangent to the curve at P is horizontal. Find the y-coordinate of P.

C) find the value of d^2y/ dx^2 at the point p found in part (B)

- calculus -
**bobpursley**, Sunday, January 11, 2009 at 8:18pm
2x dx+8ydy=3ydx + 3xdy

solve for dy/dx

Then, take the next derivative.

for B), put x=3 into the original equation, find y. Then find the slope (dy/dx) at that point.

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