Posted by Andrew on Sunday, January 11, 2009 at 7:15pm.
So what is the reaction? I'll call lactic acid HL for simplicity.
HL + NaOH ==> NaL + H2O
HL = 0.005 mols. You are correct.
NaOH = 0.001 mols. You are correct.
Now you see that an acid + base = salt + water.
So the smaller mols will react completely and leave an excess of what is left.
0.001 mol NaOH will form 0.001 mol NaL, 0.001 mol H2O, and will leave 0 mol NaOH (all of it is reacted), but 0.005 - 0.001 mol = 0.004 mols HL.
So you have an acid (0.004 mol HL) and a salt of the weak acid (0.001 NaL) so that is a buffered solution.
(NaL) = (0.001 mol/0.105 L)
(HL) = (0.004 mol/0.105 L)
The H-H equation is
pH = pKa + log (base/acid)
base is NaL
acid is HL.
lolol
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