Posted by Jane on Sunday, January 11, 2009 at 1:25pm.
Find:
1)x^2y^2=15, normal at (8,7)

Calculus  bobpursley, Sunday, January 11, 2009 at 3:34pm
first, find the slope, then the negative reciprocal of that slope.
2x dx2ydy=0
Put in x,y and find dy/dx.
Now, the normal will be y=mx+b, m is the negative reciprocal of the dy/dx above, solve for b, and you have it.
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