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September 1, 2014

September 1, 2014

Posted by **Jane** on Sunday, January 11, 2009 at 1:25pm.

1)x^2-y^2=15, normal at (-8,7)

- Calculus -
**bobpursley**, Sunday, January 11, 2009 at 3:34pmfirst, find the slope, then the negative reciprocal of that slope.

2x dx-2ydy=0

Put in x,y and find dy/dx.

Now, the normal will be y=mx+b, m is the negative reciprocal of the dy/dx above, solve for b, and you have it.

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