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August 30, 2014

August 30, 2014

Posted by **Barbara** on Thursday, January 8, 2009 at 11:37pm.

- calculus -
**drwls**, Thursday, January 8, 2009 at 11:57pmCompute the indefinite integral of(x/2) + 3.

It equals [x^2/4] + 3x

Subtract the value of that function at x=2 from the value at x=4. That will be the area under the curve.

- calculus -
**Barbara**, Friday, January 9, 2009 at 12:12amI got 7 but the answer in the book says 21

- calculus -
**drwls**, Friday, January 9, 2009 at 12:39am[x^2/4] + 3x at x= 4 is 16

[x^2/4] + 3x at x= 2 is 7

I get 9 for the answer.

Are you sure you copied the integrand correctly? Is it really (x/2) + 3 ?

I cannot explain the discrepancy

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