a force of 50 N directed at an angle of 45 from the horizontal pulls a 70 kg sled across a frictionless pond. the acceleration of the sled is most nearly

To find the acceleration of the sled, we can use Newton's second law of motion, which states that the force applied to an object is equal to the mass of the object multiplied by its acceleration:

F = m * a

In this case, the force applied to the sled is 50 N, and the mass of the sled is 70 kg.

Now, the force is not directly in the horizontal direction but at an angle of 45 degrees from the horizontal. To determine the horizontal component of the force, we need to find the cosine of the angle:

Horizontal component = Force * cos(angle)
= 50 N * cos(45 degrees)
= 50 N * 0.7071
= 35.355 N

Since there is no friction acting on the sled, the horizontal component of the applied force is the only force acting to move the sled forward. Therefore, we can equate the horizontal component of the force to the mass of the sled multiplied by its acceleration:

35.355 N = 70 kg * a

To find the acceleration (a), we can rearrange the equation:

a = 35.355 N / 70 kg
≈ 0.5051 m/s^2

Therefore, the acceleration of the sled is approximately 0.5051 m/s^2.