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August 31, 2014

August 31, 2014

Posted by **jen** on Thursday, January 8, 2009 at 4:22pm.

I got tan(theta)=[sqrt(294)]/42

Is that right?

if sin(theta)=-a where 0<a<1, and theta is in quadrant 3, find the exact algebraic expressionm for cos(theta)

- simple trig -
**Reiny**, Thursday, January 8, 2009 at 4:27pmYou said

sin(theta)=[sqrt(70)]/7

that would make

sin(theta) > 1 which is not possible

check your typing

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