Posted by Anonymous on Thursday, January 8, 2009 at 2:11pm.
C=27!/25! * 10!/8! * 4!/2!2!
The last term represents the number of permuations of two letters, two numbers can be done (six ways).
my approach:
first lets choose 2 letters and 2 numbers,
that is C(26,2)*C(10,2)
= 325*45
= 14625
let's consider one of these, say, DK45
now that could be arranged in 4! ways
so the total number of passwords is
14625*4! = 351000
bobpursley, when did they introduce that 27th letter?
Related Questions
math - Elisa need to pick a numerical password that contains 4 digits using the ...
Integrated Math 1 - A valid password on a Web site contains 3 letters (A-Z, 26 ...
Permutations - A valid password on a Web site contains 3 letters (A-Z, 26 total...
Permutations - A valid password on a Web site contains 3 letters (A-Z, 26 total...
math check my work - a license plate has 2 letters followed by 4 digits.how many...
math please check my work - a license plate has 2 letters followed by 4 digits....
Algebra - A password consists of three digits, 0 through 9, followed by three ...
Statistics - Find the possible nuber of license plates consisting of 2 letters ...
probability - you are to set up a code of consisting of three letters (A to Z) ...
Math - How many passwords can be made using 2 letters and 4 digits (this time ...
For Further Reading
