Saturday

September 20, 2014

September 20, 2014

Posted by **Phil** on Thursday, January 8, 2009 at 8:06am.

- Physics -
**drwls**, Thursday, January 8, 2009 at 9:17amThe number of moles of air in the bell remains the same. Use the reationship

PV/T = constant. Let 1 represent sea level condtions and 2 the condistions at 150 m depth.

P1*V1/T1 = P2*V2/T2

Calculate P2-P1 from the depth.

P2 - P1 = (density)*g*100 m = 1.506*10^6 N/m^2

P1 = 1 atm = 1.015*10^5 N/m^2

P2/P1 = 14.8

T2/T1 = 275/293

Solve for V2/V1 . That will equal L2/L1, the ratio of the lengths of the air column in the bell. L1 = 10 m. The distance the water rises is L1 - L2.

**Answer this Question**

**Related Questions**

Physics - Submerged Cylinder - A cylindrical diving bell 5 m in diameter and 10 ...

Physics also - A cylindrical diving bell 5 m in diameter and 10 m tall with an ...

Physics - A cylindrical diving bell 4.0m tall, with an open bottom, is lowered ...

Physics - Fluids - A cylindrical diving bell 3.0 m in diameter and 4 m tall with...

physic - you are designing a diving bell to withstand the pressure of sea water ...

physics - An evacuated spherical diving bell containing a camera is in the ocean...

math - a deep sea diving bell is being lowered at a constant rate. after 8 ...

text structure - People have used various methods to measure the depth of the ...

physics - A soft synthetic rubber ball of radius 9 cm is submerged to 7.5 m ...

college chemistry - A diving bell is a container open at the bottom. As the bell...