Wednesday
April 16, 2014

Homework Help: Calculus

Posted by Jane on Thursday, January 8, 2009 at 8:06am.

Need help to find dy/dx:

1) y = (sin x) ^-1/3

answer dy/dx = - 1/ 3(sinx) ^4/3

2) y = sqrt 8 + sin(6x)
answer - lost

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