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July 31, 2014

July 31, 2014

Posted by **Jane** on Thursday, January 8, 2009 at 8:06am.

1) y = (sin x) ^-1/3

answer dy/dx = - 1/ 3(sinx) ^4/3

2) y = sqrt 8 + sin(6x)

answer - lost

- Calculus -
**Reiny**, Thursday, January 8, 2009 at 8:48am1) close, you left out the derivative of the base, so

dy/dx = - 1/ 3(sinx) ^4/3(cosx)

for 2)

rewrite it as

y = (8+sin(6x))^1/2

dy/dx = (1/2)((8+sin(6x))^-1/2)(cos(6x))(6)

= 3cos(6x)((8+sin(6x))^-1/2)

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