Tuesday

September 23, 2014

September 23, 2014

Posted by **Jane** on Thursday, January 8, 2009 at 8:06am.

1) y = (sin x) ^-1/3

answer dy/dx = - 1/ 3(sinx) ^4/3

2) y = sqrt 8 + sin(6x)

answer - lost

- Calculus -
**Reiny**, Thursday, January 8, 2009 at 8:48am1) close, you left out the derivative of the base, so

dy/dx = - 1/ 3(sinx) ^4/3(cosx)

for 2)

rewrite it as

y = (8+sin(6x))^1/2

dy/dx = (1/2)((8+sin(6x))^-1/2)(cos(6x))(6)

= 3cos(6x)((8+sin(6x))^-1/2)

**Answer this Question**

**Related Questions**

Calculus - Can someone help me find the derivatives of these questions? For ...

calculus - Could someone check my reasoning? thanx Find the derivative of the ...

Calculus - Please look at my work below: Solve the initial-value problem. y'' + ...

calculus - Find complete length of curve r=a sin^3(theta/3). I have gone thus- (...

Calculus - More questions on - finding dy/dx 1) y = sqrt 4 + sin 10 x - I am ...

Calculus Help and Check - find the derivative of the function integral from cosx...

Calculus - Second Order Differential Equations - Posted by COFFEE on Monday, ...

Calculus - Find the dervatives: 1. f(x)=(3x+1)e^x^2 2. y = e^(sin x) ln(x) 3. f(...

Math(Please help) - 1)tan Q = -3/4 Find cosQ -3^2 + 4^2 = x^2 9+16 = sqrt 25 = 5...

calculus - (SIN^8X-5 SIN^5X+SINX)COSX DX I need the answer to this, because I ...