Posted by Phil on .
A cylindrical diving bell 5 m in diameter and 10 m tall with an open bottom is submerged to a depth of 150 m in the ocean. The temperature of the air at the surface is 20 degrees Celsius, and the air temp 150 m down is 2 degrees Celsius. The density of seawater is 1025 kg/m^3. How high does the sea water rise in the bell when the bell is submerged?
STEPS:
(1) Find volume of cylinder
(2) Find volume of air in cylinder when submerged
(3) Vcyl  Vair = Vwater
I think you use the formula P=Po + pgh to find the height of the air pocket, but I'm not sure what values to use for P, Po, and p. Please help.

Physics  Submerged Cylinder 
Dom,
h=(2*sigma*cos(theta))/(rho*g*r)
r= radius
sigma= 0.123(10.00139T)
theta=contact angle (for water=0)
rho=density