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February 1, 2015

February 1, 2015

Posted by **MissyQ** on Wednesday, January 7, 2009 at 3:57pm.

here is one of the problems. Also my computer does not show the on root sign thing.

root sign 8n^3 (to the power of three)

____

81

- Math -
**Casey**, Wednesday, January 7, 2009 at 6:16pmsince you can't find the square of 8 you look inside that number to see what other numbers can be squared.

For instance, 8 is divisible by 2 and 4. You can find the square root of 4. That is the first step.

Now on n^3 you simply put it in terms that are divisible by 2. so you can break n^3 up into n^2 and n^1 because that still equals n^3.

Now all that is left is your problem: SQUARE ROOT 2X4 n^1 N^2

since you can find the square root of 4 and n^2 can be divided by two your answer would be

2N^1 SQUARE ROOT 2 n^1

hope that helps

- Math -
**dd**, Sunday, May 22, 2011 at 11:42ami need to check my answers for my THA #27

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