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December 20, 2014

December 20, 2014

Posted by **y912f** on Wednesday, January 7, 2009 at 1:19pm.

1. a bicycle with a 28-inch wheel(diameter) travels a distance of 800 feet. how many revolutions does the wheel make (to the nearest revolution)?

2. A wheel with a 20-inch radius is marked at two points on teh rim. the distance between the marks along the wheel is found to be 3 inches. what is the angle (to the nearest tenth of a degree) between the radii to the two marks?

it would be realy helpful if you could explain to me how to figure out these two. thks

- trigonometry -
**Reiny**, Wednesday, January 7, 2009 at 1:27pm1. How far does the wheel go in 1 rotation?

C = piD = pi(28)inches

but 800 feet = 9600 inches

so no of rotations = 9600/(28pi) = 109 to the nearest whole number

for 2. is the 3 inches the straight line distance betweeen the points or is it measured along the arc?

If straight, use the Cosine Law,

If arc length, set up a ratio..

angle/360 = 3/(40pi), solve for "angle"

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