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December 10, 2016
Posted by **Jane** on Wednesday, January 7, 2009 at 12:33pm.

Find dy/dx & d^2y/dx^2

y^2 - x^2 = 2

is the answer dy/dx=x/y; d^2y/dx^2=

y^2-x^2/y^2

- Calculus -
**Reiny**, Wednesday, January 7, 2009 at 1:05pm2y(dy/dx) - 2x = 0

dy/dx = 2x/(2y) = x/y

y'' = (y(1) - x(y'))/y^2

= (y - x(x/y))/y^2

= (y^2 - x^2)/y^3

you had y^2 at the bottom of your y''

did you notice that there was a y in the denominator of your top?