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Calculus

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Answer ? - impicit differentiation

Find dy/dx & d^2y/dx^2

y^2 - x^2 = 2

is the answer dy/dx=x/y; d^2y/dx^2=
y^2-x^2/y^2

  • Calculus - ,

    2y(dy/dx) - 2x = 0
    dy/dx = 2x/(2y) = x/y

    y'' = (y(1) - x(y'))/y^2
    = (y - x(x/y))/y^2
    = (y^2 - x^2)/y^3

    you had y^2 at the bottom of your y''
    did you notice that there was a y in the denominator of your top?

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