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January 31, 2015

January 31, 2015

Posted by **Samantha** on Wednesday, January 7, 2009 at 10:48am.

4:30 pm

I am pretty sure that is incorrect. could someone please show me the correct expression to use to find the correct answer?

- algebra -
**Damon**, Wednesday, January 7, 2009 at 10:54amcall t time after a passes

distance a = 100 t

distance b = 110 (t-.5)

-----------------------

0 = 100 t -110(t-.5)

10 t = 55

5 = 5.5 hours

3:10 + 5:30 = 8:40

- algebra -
**drwls**, Wednesday, January 7, 2009 at 10:57amWhen train B passes the station, train A is (1/2 h)(100 mph) = 50 miles ahead. The distance between trains decreases at 10 miles per hour. Therefore B will catch A in five hours, at 8:10 pm

- algebra -
**drwls**, Wednesday, January 7, 2009 at 10:58amDamon is correct; I should have added the 5 hours to 3:40, not 3:10

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