Wednesday
March 22, 2017

Post a New Question

Posted by on Wednesday, January 7, 2009 at 10:48am.

Trains A and B are traveling in the same direction on parallel tracks. Train A is traveling at 100 mph and train B is traveling at 110 mph. Train A passes a station at 3:10 pm. If train B passes the same station at 3:40pm, at what time will train B catch train A?

4:30 pm

I am pretty sure that is incorrect. could someone please show me the correct expression to use to find the correct answer?

  • algebra - , Wednesday, January 7, 2009 at 10:54am

    call t time after a passes
    distance a = 100 t
    distance b = 110 (t-.5)
    -----------------------
    0 = 100 t -110(t-.5)
    10 t = 55
    5 = 5.5 hours
    3:10 + 5:30 = 8:40

  • algebra - , Wednesday, January 7, 2009 at 10:57am

    When train B passes the station, train A is (1/2 h)(100 mph) = 50 miles ahead. The distance between trains decreases at 10 miles per hour. Therefore B will catch A in five hours, at 8:10 pm

  • algebra - , Wednesday, January 7, 2009 at 10:58am

    Damon is correct; I should have added the 5 hours to 3:40, not 3:10

Answer This Question

First Name:
School Subject:
Answer:

Related Questions

More Related Questions

Post a New Question