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Trains A and B are traveling in the same direction on parallel tracks. Train A is traveling at 100 mph and train B is traveling at 110 mph. Train A passes a station at 3:10 pm. If train B passes the same station at 3:40pm, at what time will train B catch train A?

4:30 pm

I am pretty sure that is incorrect. could someone please show me the correct expression to use to find the correct answer?

  • algebra -

    call t time after a passes
    distance a = 100 t
    distance b = 110 (t-.5)
    0 = 100 t -110(t-.5)
    10 t = 55
    5 = 5.5 hours
    3:10 + 5:30 = 8:40

  • algebra -

    When train B passes the station, train A is (1/2 h)(100 mph) = 50 miles ahead. The distance between trains decreases at 10 miles per hour. Therefore B will catch A in five hours, at 8:10 pm

  • algebra -

    Damon is correct; I should have added the 5 hours to 3:40, not 3:10

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