find the equation of a line with a slpoe of -2 that passes through the point (4,3).
y=-2x+b
Plug and chug
3=-2(4)
3=-8
-8 both sides
-5=b
equation is
y=-2x-5
ok,so you multiply the m and x and take away the 8 from both sides of the = sign?
Sorry,I'm just trying to understand how to get the answer so I can figure out other problems.
To find the equation of a line with a given slope that passes through a specific point, you can use the point-slope form of a linear equation. The point-slope form is given by:
y - y1 = m(x - x1),
where (x1, y1) represents the given point and m represents the slope of the line.
In this case, the slope is -2, and the given point is (4,3). Let's substitute these values into the equation:
y - 3 = -2(x - 4).
Next, simplify the equation:
y - 3 = -2x + 8.
To find the equation in slope-intercept form, where the equation is in the form y = mx + b (m represents the slope and b represents the y-intercept), rearrange the equation:
y = -2x + 8 + 3.
Finally, simplify the equation:
y = -2x + 11.
Therefore, the equation of the line with a slope of -2 that passes through the point (4,3) is y = -2x + 11.