a man and a woman are sitting .5m away from each other. the man has a mass of 75 kg and the woman has a mass of 65 kg. what is the attractive force between them due to gravity?
F = G M1 M2 / d^2
F = 6.67 * 10^-11 * 75 *65 / .25
To calculate the attractive force between the man and woman due to gravity, we can use Newton's Law of Universal Gravitation.
The formula for gravitational force is:
F = (G * m1 * m2) / d^2
Where:
F is the gravitational force
G is the gravitational constant (approximately 6.67430 × 10^-11 N*m^2/kg^2)
m1 and m2 are the masses of the two objects
d is the distance between the centers of the two objects
Let's plug in the values:
m1 = 75 kg
m2 = 65 kg
d = 0.5 m
G = 6.67430 × 10^-11 N*m^2/kg^2
F = (6.67430 × 10^-11 N*m^2/kg^2 * 75 kg * 65 kg) / (0.5 m)^2
Now, let's simplify the equation:
F = (6.67430 × 10^-11 N*m^2/kg^2 * 75 kg * 65 kg) / (0.5 m)^2
F = (6.67430 × 10^-11 N*m^2/kg^2 * 75 kg * 65 kg) / (0.25 m^2)
F = (3.00803 × 10^-7 N*m^2/kg^2 * 75 kg * 65 kg) / (0.25 m^2)
F = (3.00803 × 10^-7 N*m^2/kg^2 * 4875 kg^2) / (0.25 m^2)
F = 3.00803 × 10^-7 N*m^2/kg^2 * 1953125 kg^2 / (0.25 m^2)
F = 5.86162 N
Therefore, the attractive force between the man and woman due to gravity is approximately 5.86162 Newtons.