Sunday
May 19, 2013

# Homework Help: Physics

Posted by Megan on Sunday, January 4, 2009 at 9:14pm.

A yo-yo has a string length of 0.200 m

What is the slowest speed at which you can spin it to keep it in a fixed path?

What is this, and how do you find it?
Thanks

• Physics - bobpursley, Sunday, January 4, 2009 at 9:29pm

define "fixed path"

• Physics - Megan, Sunday, January 4, 2009 at 9:34pm

The question just says "the slowest speed at which you can spin it to keep it in a fixed path"

• Physics: HELP NEEDED - bobpursley, Sunday, January 4, 2009 at 9:37pm

Ok, then I can't help, a fixed path is a straight line. I can't imagine that with a yo-yo. So if it is in a circle, is it horizontal circle or vertical. Normally a yoyo would be operating in a vertical orbit, but that hardly is a fixed path. I will see if I can get you some other eyes on this.

• Physics - Megan, Sunday, January 4, 2009 at 9:45pm

Im sorry, I forgot...

Its a vertical circle.

• Physics - Damon, Monday, January 5, 2009 at 1:42am

If it is a vertical path then and it is sleeping at the end of the string, it is like a rock at the end of a string and the centripetal acceleration at the top of the loop must be equal or greater than 1 g or the string will go slack and the rock fall out of the vertical circle.
v^2/r >/= g for circular path
so v at least sqrt ( g r )
v = sqrt (9.8 * .2) = sqrt (1.96)
v = 1.4 m/s

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